各位用户为了找寻关于一列保存多个ID(将多个用逗号隔开的ID转换成用逗号隔开的名称)的资料费劲了很多周折。这里教程网为您整理了关于一列保存多个ID(将多个用逗号隔开的ID转换成用逗号隔开的名称)的相关资料，仅供查阅，以下为您介绍关于一列保存多个ID(将多个用逗号隔开的ID转换成用逗号隔开的名称)的详细内容
背景：在做项目时，经常会遇到这样的表结构在主表的中有一列保存的是用逗号隔开ID。如，当一个员工从属多个部门时、当一个项目从属多个城市时、当一个设备从属多个项目时，很多人都会在员工表中加入一个deptIds VARCHAR(1000)列（本文以员工从属多个部门为例），用以保存部门编号列表（很明显这不符合第一范式，但很多人这样设计了，在这篇文章中我们暂不讨论在这种应用场景下，如此设计的对与错，有兴趣的可以在回复中聊聊），然后我们在查询列表中需要看到这个员工从属哪些部门。 初始化数据： 部门表、员工表数据：
代码如下:
IF EXISTS (SELECT * FROM sys.objects WHERE object_id = OBJECT_ID(N'[dbo].[Department]')) DROP TABLE [dbo].Department GO --部门表 CREATE TABLE Department ( id int, name nvarchar(50) ) INSERT INTO Department(id,name) SELECT 1,'人事部' UNION SELECT 2,'工程部' UNION SELECT 3,'管理部' SELECT * FROM Department IF EXISTS (SELECT * FROM sys.objects WHERE object_id = OBJECT_ID(N'[dbo].[Employee]')) DROP TABLE [dbo].Employee GO --员工表 CREATE TABLE Employee ( id int, name nvarchar(20), deptIds varchar(1000) ) INSERT INTO Employee(id,name,deptIds) SELECT 1,'蒋大华','1,2,3' UNION SELECT 2,'小明','1' UNION SELECT 3,'小华','' SELECT * FROM Employee
希望得到的结果：
解决方法： 第一步，是得到如下的数据。即将员工表集合与相关的部门集合做交叉连接，其中使用了fun_SplitIds函数（作用是将ids分割成id列表），然后员工集合与这个得到的集合做交叉连接
代码如下:
SELECT E.*,ISNULL(D.name,'') AS deptName FROM Employee AS E OUTER APPLY dbo.fun_SplitIds(E.deptIds) AS DID LEFT JOIN Department AS D ON DID.ID=D.id;
第二步，已经得到了如上的数据，然后要做的就是根据ID分组，并对deptName列做聚合操作，但可惜的是SQL SERVER还没有提供对字符串做聚合的操作。但想到，我们处理树形结构数据时，用CTE来做关系数据，做成有树形格式的数据，如此我们也可以将这个问题转换成做树形格式的问题，代码如下：
代码如下:
;WITH EmployeT AS( --员工的基本信息(使用OUTER APPLY将多个ID拆分开来,然后与部门表相关联) --此时已将员工表所存的IDS分别与部门相关联,下面需要将此集合中的deptName聚合成一个记录 SELECT E.*,ISNULL(D.name,'') AS deptName FROM Employee AS E OUTER APPLY dbo.fun_SplitIds(E.deptIds) AS DID LEFT JOIN Department AS D ON DID.ID=D.id ),mike AS( SELECT id,name,deptIds,deptName ,ROW_NUMBER()OVER(PARTITION BY id ORDER BY id) AS level_num FROM EmployeT ),mike2 AS( SELECT id,name,deptIds,CAST(deptName AS NVARCHAR(100)) AS deptName,level_num FROM mike WHERE level_num=1 UNION ALL SELECT m.id,m.name,m.deptIds,CAST(m2.deptName+','+m.deptName AS NVARCHAR(100)) AS deptName,m.level_num FROM mike AS m INNER JOIN mike2 AS m2 ON m.ID=m2.id AND m.level_num=m2.level_num+1 ),maxMikeByIDT AS( SELECT id,MAX(level_num) AS level_num FROM mike2 GROUP BY ID ) SELECT A.id,A.name,A.deptIds,A.deptName FROM mike2 AS A INNER JOIN maxMikeByIDT AS B ON A.id=B.ID AND A.level_num=B.level_num ORDER BY A.id OPTION (MAXRECURSION 0)
结果如下：
全部SQL：
代码如下:
IF EXISTS (SELECT * FROM sys.objects WHERE object_id = OBJECT_ID(N'[dbo].[Department]')) DROP TABLE [dbo].Department GO --部门表 CREATE TABLE Department ( id int, name nvarchar(50) ) INSERT INTO Department(id,name) SELECT 1,'人事部' UNION SELECT 2,'工程部' UNION SELECT 3,'管理部' SELECT * FROM Department IF EXISTS (SELECT * FROM sys.objects WHERE object_id = OBJECT_ID(N'[dbo].[Employee]')) DROP TABLE [dbo].Employee GO --员工表 CREATE TABLE Employee ( id int, name nvarchar(20), deptIds varchar(1000) ) INSERT INTO Employee(id,name,deptIds) SELECT 1,'蒋大华','1,2,3' UNION SELECT 2,'小明','1' UNION SELECT 3,'小华','' SELECT * FROM Employee --创建一个表值函数，用来拆分用逗号分割的数字串，返回只有一列数字的表 IF EXISTS (SELECT * FROM sys.objects WHERE object_id = OBJECT_ID(N'[dbo].[fun_SplitIds]')) DROP FUNCTION [dbo].fun_SplitIds GO CREATE FUNCTION dbo.fun_SplitIds( @Ids nvarchar(1000) ) RETURNS @t_id TABLE (id VARCHAR(36)) AS BEGIN DECLARE @i INT,@j INT,@l INT,@v VARCHAR(36); SET @i = 0; SET @j = 0; SET @l = len(@Ids); while(@j < @l) begin SET @j = charindex(',',@Ids,@i+1); IF(@j = 0) set @j = @l+1; SET @v = cast(SUBSTRING(@Ids,@i+1,@j-@i-1) as VARCHAR(36)); INSERT INTO @t_id VALUES(@v) SET @i = @j; END RETURN; END GO ;WITH EmployeT AS( --员工的基本信息(使用OUTER APPLY将多个ID拆分开来,然后与部门表相关联) --此时已将员工表所存的IDS分别与部门相关联,下面需要将此集合中的deptName聚合成一个记录 SELECT E.*,ISNULL(D.name,'') AS deptName FROM Employee AS E OUTER APPLY dbo.fun_SplitIds(E.deptIds) AS DID LEFT JOIN Department AS D ON DID.ID=D.id ),mike AS( SELECT id,name,deptIds,deptName ,ROW_NUMBER()OVER(PARTITION BY id ORDER BY id) AS level_num FROM EmployeT ),mike2 AS( SELECT id,name,deptIds,CAST(deptName AS NVARCHAR(100)) AS deptName,level_num FROM mike WHERE level_num=1 UNION ALL SELECT m.id,m.name,m.deptIds,CAST(m2.deptName+','+m.deptName AS NVARCHAR(100)) AS deptName,m.level_num FROM mike AS m INNER JOIN mike2 AS m2 ON m.ID=m2.id AND m.level_num=m2.level_num+1 ),maxMikeByIDT AS( SELECT id,MAX(level_num) AS level_num FROM mike2 GROUP BY ID ) SELECT A.id,A.name,A.deptIds,A.deptName FROM mike2 AS A INNER JOIN maxMikeByIDT AS B ON A.id=B.ID AND A.level_num=B.level_num ORDER BY A.id OPTION (MAXRECURSION 0)