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比如有文章表 Article(Id,Category,InsertDate),现在要用SQL找出每种类型中时间最新的前N个数据组成的集合,一段不错的代码,留存备用
? 1 2 3 4 5 6 7 8 9 10 11 12 13SELECT
A1.*
FROM
Article
AS
A1
INNER
JOIN
(
SELECT
A.Category,A.InsertDate
FROM
Article
AS
A
LEFT
JOIN
Article
AS
B
ON
A.Category = B.Category
AND
A.InsertDate <= B.InsertDate
GROUP
BY
A.Category,A.InsertDate
HAVING
COUNT
(B.InsertDate) <= @N
)
AS
B1
ON
A1.Category = B1.Category
AND
A1.InsertDate = B1.InsertDate
ORDER
BY
A1.Category,A1.InsertDate
DESC
@N 就是你要取多少条
下面是我用到了一个产品分类表中,superId是大分类,prcid是产品分类。能用SQL完成的功能就要尽量用SQL语句来完成,这既简洁又高效。
? 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22SELECT
A1.*
FROM
prcKx
AS
A1
INNER
JOIN
(
SELECT
A.superId,
A.prcid
FROM
prcKx
AS
A
LEFT
JOIN
prcKx
AS
B
ON
A.superId = B.superId
AND
A.prcid <= B.prcid
GROUP
BY
A.superId,
A.prcid
HAVING
COUNT
(B.prcid) <= 7
)
AS
B1
ON
A1.superId = B1.superId
AND
A1.prcid = B1.prcid
ORDER
BY
superId,
prcid
需求是这样的(CSDN上的一个问题):mysql中有个表:article(字段:id,type,date),type有1-10,10种类型。现在要用SQL找出每种类型中时间最新的前N个数据组成的集合。
这个问题应该有很多方法可以实现,下面就来说说在网上看到的一位高手的实现(用一条SQL语句实现的,个人感觉非常好,所以拿来和大家分享):
? 1 2 3 4 5 6 7 8 9select
a1.*
from
article a1
inner
join
(
select
a.type,a.
date
from
article a
left
join
article b
on
a.type=b.type
and
a.
date
<=b.
date
group
by
a.type,a.
date
having
count
(b.
date
)<=2
)b1
on
a1.type=b1.type
and
a1.
date
=b1.
date
order
by
a1.type,a1.
date
desc
注:上面sql语句中的2代表的就是前面提到的N。
以上所述就是本文的全部内容了,希望大家能够喜欢。