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语法规则
? 1 2 3 4SELECT column_name(s)
FROM table_name1
INNER JOIN table_name2
ON table_name1.column_name=table_name2.column_name
先创建两个表,1.用户,2.用户类别
用户表
? 1 2 3 4 5 6CREATE TABLE `user` (
`id` int(32) NOT NULL AUTO_INCREMENT,
`name` varchar(16) NOT NULL,
`kindid` int(32) NOT NULL,
PRIMARY KEY (`id`)
) ENGINE=MyISAM DEFAULT CHARSET=utf8;
用户类别表
? 1 2 3 4 5CREATE TABLE `userkind` (
`id` int(32) NOT NULL AUTO_INCREMENT,
`kindname` varchar(16) NOT NULL,
PRIMARY KEY (`id`)
) ENGINE=MyISAM DEFAULT CHARSET=utf8;
插入一些数据到user表
INSERT INTO `user` VALUES (1,'小明',1),(2,'小红',1),(3,'涵涵',2);插入一些数据到 userkind表
INSERT INTO `userkind` VALUES (1,'普通会员'),(2,'VIP会员');
如图:
下面是控制台的查询例子:
? 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 61 62 63 64 65 66 67 68 69 70 71Enter password: ****
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mysql> use join;
Database changed
mysql> select * from `user`;
+----+------+--------+
| id | name | kindid |
+----+------+--------+
| 1 | 小明 | 1 |
| 2 | 小红 | 1 |
| 3 | 涵涵 | 2 |
+----+------+--------+
3 rows in set (0.00 sec)
mysql> select * from `userkind`;
+----+----------+
| id | kindname |
+----+----------+
| 1 | 普通会员 |
| 2 | VIP会员 |
+----+----------+
2 rows in set (0.00 sec)
mysql> select * from `user` inner join `userkind` on user.kindid=userkind.id;
+----+------+--------+----+----------+
| id | name | kindid | id | kindname |
+----+------+--------+----+----------+
| 1 | 小明 | 1 | 1 | 普通会员 |
| 2 | 小红 | 1 | 1 | 普通会员 |
| 3 | 涵涵 | 2 | 2 | VIP会员 |
+----+------+--------+----+----------+
3 rows in set (0.02 sec)
mysql> select `id` as `用户ID`,`name` as `用户名`,`kindname` as `用户类别` from
`user` inner join `userkind` where user.kindid=userkind.id;
ERROR 1052 (23000): Column 'id' in field list is ambiguous
mysql> select `user`.`id` as `用户ID`,`name` as `用户名`,`kindname` as `用户类别
` from
-> `user` inner join `userkind` where `user`.`kindid`=`userkind`.`id`;
+--------+--------+----------+
| 用户ID | 用户名 | 用户类别 |
+--------+--------+----------+
| 1 | 小明 | 普通会员 |
| 2 | 小红 | 普通会员 |
| 3 | 涵涵 | VIP会员 |
+--------+--------+----------+
3 rows in set (0.00 sec)
mysql> select `user`.`id` as `用户ID`,`name` as `用户名`,`kindname` as `用户类别
` from `user` inner join `userkind` on `user`.`kindid`=`userkind`.`id`;
+--------+--------+----------+
| 用户ID | 用户名 | 用户类别 |
+--------+--------+----------+
| 1 | 小明 | 普通会员 |
| 2 | 小红 | 普通会员 |
| 3 | 涵涵 | VIP会员 |
+--------+--------+----------+
3 rows in set (0.00 sec)
mysql>
需要注意的是: 这里的on 基本等价于where(本人感觉)
当 column (字段) 两个表都有 却分不清时,需要用`表名`.`字段名` 进行分辨。
as就是取别名了。看上面例子就知道!
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