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在PostgreSQL数据库中有一列为JSON,要获取JSON中得数据可以用下面sql:

? 1 2 3 4 5 6 7 8 9 select orderno as OrderNo  ,amount as Amount  ,ordertime as OrderTime  , recordtype as RecordType from jsonb_to_recordset(( --特定方法   select array_to_json(array_agg(data)) --转换成一个数组   from wallet_details   where id = @id   )::jsonb) as x(orderno text, amount numeric(16, 6), ordertime text, recordtype varchar(32));

如果你获取得数据是当前行,但是JSON中也要取出来几个值可以用下面的方式获取:

? 1 2 3 4 5 6 select pay_params::json->>'Key' as Md5Key ,   pay_params::json->>'AppId' as Appid ,   pay_params::json->>'MchId' as Mchid ,   pay_params::json->>'SubMchId' as Submchid ,   tenant_id as Tenant_Id   from spm_wallet_settings where id='12'

补充:PostgreSql数据库sql语句取Json值

1:json字段实例:

 

? 1 2 3 4 5 { “boxNum”: 0, “orderNum”: 0, “commentNum”: 0 }

A.取boxNum的值

1.1)select 字段名->‘boxNum' from 表名;

1.2)select jsonb_extract_path_text字段名, ‘boxNum') from 表名;

2:json字段实例:

 

? 1 2 3 4 5 { “boxNum”: “0”, “orderNum”: “0”, “commentNum”: “0” }

A.取boxNum的值,不带双引号。

2.1)select 字段名->>‘boxNum' from 表名;

2.2)select jsonb_extract_path_text字段名, ‘boxNum') from 表名;

3:json字段实例:

 

? 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 { “unitPrices”: [{ “price”: 10.0, “unitId”: “8”, “unitName”: “500克”, “unitAmount”: “0”, “isPMDefault”: true, “isHomeDefault”: true, “originalPrice”: 10.0 }], “productName”: “远洋 加拿大 螯龙虾 野生捕捞”, “productType”: 1, “skuPortRate”: { “id”: “a6b83048-3878-4698-88c2-2a9de288ac56”, “cityId”: “2bf8c60c-789d-433a-91ae-8e4ae3e587a4”, “dynamicProperties”: [{ name”: “死亡率”, “propertiesId”: “f05bda8c-f27c-4cc6-b97e-d4bd07272c81”, “propertieValue”: { “value”: “2.0” } }, { name”: “失水率”, “propertiesId”: “ee9d95d7-7e28-4d54-b572-48ae64146c46”, “propertieValue”: { “value”: “3.0” } }] }, “quotePriceAttribute”: { “currencyName”: “人民币” } }

A.取quotePriceAttribute中的currencyName币制名称

? 1 select (字段名>>‘quotePriceAttribute')::json->>‘currencyName' from 表名;

B.取unitPrices中的price单价

? 1 select jsonb_array_elements((字段名->>‘unitPrices')::jsonb)->>‘price' from 表名;

C.取skuPortRate中的dynamicProperties的name为死亡率的propertieValue里面的value;

? 1 2 select bb->‘propertieValue'->>‘value' as value from ( select jsonb_array_elements(((字段名->>‘skuPortRate')::json->>‘dynamicProperties')::jsonb) as bb from 表名) as dd where dd.bb @> ‘{“name”: “死亡率”}';

4.json字段实例:

 

? 1 2 3 4 5 6 [{“name”: “捕捞方式”, “showType”: 4, “propertiesId”: “9a14e435-9688-4e9b-b254-0e8e7cee5a65”, “propertieValue”: {“value”: “野生捕捞”, “enValue”: “Wild”}}, {“name”: “加工方式”, “showType”: 4, “propertiesId”: “7dc101df-d262-4a75-bdca-9ef3155b7507”, “propertieValue”: {“value”: “单冻”, “enValue”: “Individual Quick Freezing”}}, {“name”: “原产地”, “showType”: 4, “propertiesId”: “dc2b506e-6620-4e83-8ca1-a49fa5c5077a”, “propertieValue”: {“value”: “爱尔兰”, “remark”: “”, “enValue”: “Ireland”}}]

–获取原产地

? 1 2 3 4 5 6 select (SELECT ss->‘propertieValue' as mm FROM (SELECT jsonb_array_elements (dynamic_properties) AS ss FROM product where id=a.id) as dd where dd.ss @> ‘{“name”: “原产地”}')->>‘value' as cuntry, a.* from product as a where a.id=‘633dd80f-7250-465f-8982-7a7f01aaeeec'

5:json例子:huren:[“aaa”,“bbb”,“ccc”…]

 

需求:取值aaa去““双引号”

? 1 select replace(cast(jsonb_array_elements(huren) as text), ‘"','') from XXX limit 1

以上为个人经验,希望能给大家一个参考,也希望大家多多支持。如有错误或未考虑完全的地方,望不吝赐教。

原文链接:https://www.cnblogs.com/ljknlb/p/11734145.html